5 years ago, age of p was 4 times that of z. the sum of their present age is 55.find p's present age
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Hi friend
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Your answer
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SOLVING (BY METHOD OF COMPARISON)
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LET P's PRESENT AGE BE X YEARS AND Z's PRESENT AGE BE Y YEARS.
THEN,
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X - 5 = 4(Y - 5).........(1)
AGAIN,
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X + Y = 55............(2)
FROM, EQ.(1), WE GET,
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X - 5 = 4(Y-5)
X-5=4Y - 20
Y = (X+15)/4........ (3)
FROM EQ.(2), WE GET,
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X + Y = 55
Y = 55 - X............(4)
ON COMPARING THE VALUES OF Y FROM EQ. (3)&(4), WE GET,
(X+15)/4 = 55-X
X + 15 = 4(55-X)
X + 15 = 220 - 4X
X + 4X = 220 - 15
5X = 205
X = 205/5
X = 41
THEREFORE,
--------------------
AGE OF P = X YEARS = 41 YEARS
HOPE IT HELPS
#ARCHITECTSETHROLLINS
-------------
Your answer
-------------------
SOLVING (BY METHOD OF COMPARISON)
------------------------------------------------------------------
LET P's PRESENT AGE BE X YEARS AND Z's PRESENT AGE BE Y YEARS.
THEN,
----------
X - 5 = 4(Y - 5).........(1)
AGAIN,
----------
X + Y = 55............(2)
FROM, EQ.(1), WE GET,
------------------------------------
X - 5 = 4(Y-5)
X-5=4Y - 20
Y = (X+15)/4........ (3)
FROM EQ.(2), WE GET,
----------------------------------
X + Y = 55
Y = 55 - X............(4)
ON COMPARING THE VALUES OF Y FROM EQ. (3)&(4), WE GET,
(X+15)/4 = 55-X
X + 15 = 4(55-X)
X + 15 = 220 - 4X
X + 4X = 220 - 15
5X = 205
X = 205/5
X = 41
THEREFORE,
--------------------
AGE OF P = X YEARS = 41 YEARS
HOPE IT HELPS
#ARCHITECTSETHROLLINS
ArchitectSethRollins:
please mark my answer as brainliest
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