Math, asked by nandekhushal, 11 days ago

5 years ago (back) father's age was 5 times that of his son. After 3 years, father's age would be 3 times that of his son. Find their present ages.​

Answers

Answered by kharatdevraj7
0

Answer:

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Step-by-step explanation:

5 years ago, the father's age was 5 times as old as his son and after 3 years he will be 3 times as old his son. ∴ The present age of son is 13 years.

Answered by brainlySrijan167
2

Answer:

The age of the father 5 yr ago was 5 times the age of his son. At present the father's age is 3 times that of his son. What is the present age of the father?

Solution: (F-5) = 5(S-5), or

F-5 = 5S-25, or

F = 5S-20 …(1)

F = 3S …(2)

Equate (1) and (2)

5S-20 = 3S.

2S = 20, or S = 10 and so F = 30.

The father is 30 years, now

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