Question

5 years ago, father's age was 5 times as
old as his son and after 3 years, he will be
3 times as old as his son. Find the present
age of son.

Answer 1

x-5 = 5[y-3]

x-5 = 5y-15

x-5y = -10     ,<1

x+3 = 3[y+3]

x+3 = 3y +9

X-3y = 6        ,<2

bye using elimination method for eq 1 and 2 values of x and y will be got

if u will not able that u can comment i will ans   rather try urself

Answer 2

assuming the present age of boy is B and father is F
then we start to solve as in the picture

hope understand if not u are free to ask