Math, asked by udit8781, 10 months ago

5 years ago, father's age was 7 times the age of his son

Answers

Answered by abhisheklala2802
0

Answer:

age of father 7 (x-5)

Step-by-step explanation:

let the age of son is x

5 years ago

age of son x-5

age of father 7 (x-5)

Answered by Anonymous
0

Answer:

Step-by-step explanation:

Let son's age be x years and father's age be y

5 years ago,son's age be (x+5) years

5 years ago ,father's age be (y+5)years

(y+5)=7(x+5)

y+5=7x+35

y-7x=35-5

y-7x=30

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