5 years ago fothers age was 7 times his son age and 5 years later his age will be 3 times his son age find present ages
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Answer:
Step-by-step explanation:
present age of father= x
present age of son=y
so, x-5 = 7(y-5)
= x-5 = 7y - 35
x-7y = -30 ------1
then, x+5 = 3(y+5)
x+5 = 3y + 15
x-3y = 10--------2
so by elimination method,
y=10
so x - 3(10) = 10
so x=40
so father age is 40 and his sons age is 10
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