5 years ago Gori was thrice as old as Ganesh 10 years later Gori will be twice as old as Ganesh how old are Gauri and Ganesh
Answers
Answered by
28
And
5 years ago..
Age of Ganesh = (x - 5) years
Age of Gori = (3x - 5) years.
10 years later..
Age of Ganesh = (x + 10 + 5) = (x + 15) years
Age of Gori = (3x + 10 + 5) = (3x + 15) years
A.T.Q.
3x + 15 = 2(x + 15)
3x + 15 = 2x + 30
3x - 2x = 30 - 15
x = 15
So..
= x + 5
=> 15 + 5 =
= 3x + 5
=> 3(15) + 5 =
And
5 years ago.. (Gori was thrice as old as Ganesh)
x - 5 = 3(y - 5)
x - 5 = 3y - 15
x - 3y = - 15 + 5
....(1)
10 years later.. (Gori will be twice as old as Ganesh)
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x - 2y = 20 - 10
x - 2y = 10
...(2)
Put value of x in (1)
(10 + 2y) - 3y = - 10
10 + 2y - 3y = - 10
10 - y = - 10
- y = - 10 - 10
- y = - 20
y = 20
Put value of y in (2)
x = 10 + 2(20)
x = 10 + 40
x = 50
= y years
=
= x years
=
Answered by
16
» A.T.Q.
• 5 years later (before means substraction) Gori was trice as old as Ganesh.
In this question we have to find the age of Gori and Ganesh.
Let age of Gori be M and Ganesh be A.
=> M - 5 = 3(A - 5)
=> M - 5 = 3A - 15
=> M = 3A - 15 + 5
=> M = 3A - 10 __(eq. 1)
_________________________________
• 10 years later (addition) Gori will be twice as old as Ganesh.
=> M + 10 = 2(A + 10)
=> M + 10 = 2A + 20
=> M = 2A + 20 - 10
=> M = 2A + 10
=> 3A - 10 = 2A + 10 [From eq. (1)]
=> 3A - 2A = 10 + 10
=> A = 20
Put value of A in eq. (1)
=> M = 3(20) - 10
=> M = 60 - 10
=> M = 50
__________________________________
So, Age of Gori = M = 50 years
And
Age of Ganesh = A = 20 years.
____________________[ANSWER]
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