Question

5 years ago joy was thrice as old as Mary and 10 years later Joy shall be twice as old as Mary. what are the present ages of joy and
Mary

Answer 1

Hi friend
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Your answer
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Let the age of joy be x and age of Mary be y.

Then,
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Equations
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(x - 5) = 3(y - 5).......... (i)

(x + 10) = 2(y + 10).........(ii)

From equation (i), we get,
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(x - 5) = 3(y - 5)

x - 5 = 3y - 15

x = 3y - 15 + 5

x = 3y -10...... (iii)

Again,
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From equation (ii), we get,
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(x + 10) = 2(y + 10)

x + 10 = 2y + 20

x = 2y + 20 - 10

x = 2y + 10........ (iv)

SOLVING (BY METHOD OF COMPARISON)
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On comparing the values of x from equation (iii) and (iv), we get,
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3y - 10 = 2y + 10

3y - 2y = 10 + 10

y = 20

Then,
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Mary's age = y = 20 years

Joy's age = x = 2y + 10 = 2*20 + 10 = 40 + 10 = 50 years

HOPE IT HELPS

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