Question

5 years ago luckee was 3 times as old as lovely 10 years later luckee would be twice as old as lovely how old are they now

Answer 1

let the age of luckee = X
let the age of lovely = Y

5 years ago
x-5 = y-5
x-5= (y-5)3
x-5=3y-15
x-3y = -10….................(1)

After 10 year
x+10 = y+10
x+10= 2(y+10)
x+10= 2y +20
x-2y = 10 ......................(2)

By elimaination method

x-3y = -10
x-2y = 10
- + -
-------------
-y = -20
y = 20

Put the value of y in eq 1

x-3y = -10
x-(3×20) = -10
x-60 = -10
x = -10+60
x = 50

Age of Luckee = 50 year
Age of Lovely = 20 year