Math, asked by chandrasheakarduraga, 3 months ago

5 years ago,mamta was thrice as old as sneha,ten years later,mamta will be twice as old as sneha find the present age of each​

Answers

Answered by harpinder3538
0

Answer:

50 years

Step-by-step explanation:

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Answered by Anonymous
3

ANSWER

Five years ago

Age of Nuri = x – 5 years

Age of Sony = y – 5 years

Nuri was thrice as old as Sonu

X- 5 = 3(y – 5)

X – 5 = 35 – 15

X – 3y = -15 + 5

X – 3 y = - 10 ………..(1)

Ten years later,

Age of Nuri = x + 10

Age of Sonu = y + 10

Nuri will be twice as old as Sonu.

X+ 10 = 2(y+10)

X + 10 = 2y + 20

X – 2y = 10 ………..(2)

X – 3 y = - 10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3×20=−10

X = 60 – 10

X=50

Hence age of Nuri=50 years and age of Sonu=20 years

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