Question

5 years ago maruti was thrice old as Sonu . 10 years later maruti will be twice as old as Sony how older maruti or sonu​

Answer 1

Step-by-step explanation:

let the age of maruti be x years and

let the age of sonu be y years

5 years ago ,the age of maruti is x-5

5 years ago the age of sonu is y-5

ATP,

x-5=3(y-5)

on further simplification we get,

x-3y+10=0-------------->equation 1

in second condition

10 years later the age of maruti is x+10

10 years later the age of sonu is y+10

ATP,

x+10=2(y+10)

on further simplification we get

x-2y-10=0-------------->equation 2

by elimination method we get

y=20

on substituting y value in equation 1

we get x value =50

there fore the age of maruti is 50 years

and the age of sonu is 20 years old

.....................................................................................................

Answer 2

Hey friend,

Here is the solution :-

Let Maruti's age be x and Sonu's age be y

First condition = Five years ago,

Maruti's age = ( x - 5 )

Sonu's age = ( y - 5 )

Maruti was thrice the age of Sonu

=> ( x - 5 ) = 3 ( y - 5 )

=> x - 5 = 3y - 15

=> x - 3y = - 10 ...(eqn. 1)

Second condition = Ten years hence,

Maruti's age = ( x + 10 )

Sonu's age = ( y + 10 )

Maruti will be twice of Sonu

=> ( x + 10 ) = 2 ( y + 10 )

=> x + 10 = 2y + 20

=> x - 2y = 10 .....(eqn. 2)

Now subtract the eqn. 2 from eqn. 1

=> x - 3y = - 10

(-) x - 2y = 10

(-) (+) (-)

=> y = 20

Now, substitute y = 20 in eqn. 1

=> x - 3 (20) = - 10

=> x - 60 = - 10

=> x = - 10 + 60

=> x = 50

So, here we get Maruti's age (x) = 50 years and that of Sonu (y) = 20.

✨I hope this will help you.... ✨