5 years ago mohan was 3 times as old as kavitha if the present age of mohan and kavitha are x+2. 'x' respectively write the equation for the statement
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Step-by-step explanation:
GIVEN :
- 5 years ago mohan was 3 times as old as kavitha if the present age of mohan and kavitha are x+2. 'x' respectively write the equation for the statement
to find :
write the equation for the statement
solution :
- Let mohan present age be x
- And kavita present age be y
- mohan is twice as old as kavita :
- x = 2y
- Their ages before 5 years:
- mohan age = x-5
- kavitha age = y-5
- Five years ago, his age was three times Kavitha age
- x-5= 3(y-5)
- x-5 = 3y-15
- x-3y = -15+5
- 2y-3y = -10
- -y = -10
- y = 10
- Therefore,x = 2(10) = 20
- The present age of mohan is 20 years and present age of kavitha is 10 years.
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