Question

5 years ago,nuri was twice as old as sonu.ten years later nuri will be twice as old as sonu.how opd are nuri and sonu?

Answer 1

Answer:

$\huge{\pink{\boxed{\green{\sf{AGE\:OF\:NURI=50\:years}}}}}$

$\huge{\pink{\boxed{\green{\sf{AGE\:OF\:SONU=20\:years}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

☆ Let present age of Nuri = x

☆ Present age of sonu = y

☆ According to given information:

$\to (x - 5) = 3(y - 5) \\ \to x - 3y = - 10 - - - - - (1)\\ \\ \to (x + 10) = 2(y + 10) \\ \to x - 2y = 10 - - - - - (2)$

☆ Subtracting eqn (1) from eqn (2)

$\to x - 2y - (x - 3y) = 10 - ( - 10) \\ \to x - 2y - x + 3y = 10 + 10 \\ { \pink{ \boxed{ \green{ \therefore y = 20}}}} \\ \\ substituting \:value \: of \: y \: in \: (1) \\ \to x - 3 \times 20 = - 10 \\ \to x - 60 = - 10 \\ \to x = - 10 + 60 \\ { \pink{ \boxed{ \green{ \therefore x = 50}}}} \\ \\ { \pink{ \boxed{ \green{ \therefore age \: of \: nuri = x= 50years}}}} \\ { \pink{ \boxed{ \green{ \therefore age \: of \: sonu = y = 20years}}}}$

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Answer 2

Answer:

$\huge{\mathcal{\underline{\green{Answer}}}}$

Let the present age of Nuri =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10 ………..(1)

Ten years later,

Age of Nuri =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10 ………..(2)

X–3y=−10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3×20=−10

X=60–10

X=50

Hence age of Nuri =50 years and age of Sonu =20 years