Question

5 years ago, sister's age was 5 times the age of her brother and the sum of present ages of sister and brother is34 years.what will be the age of her brother after 6 years?

Answer 1

Five years ago let the brother’s age be x. Therefore, the sister’ age will be 5x.

After 5 years (which is now), their current ages will be x + 5 and 5x + 5 respectively.

Given that the sum of their present ages is 34.

That is:

x + 5 + 5x + 5 = 34

6x + 10 = 34

6x = 34 – 10

6x = 24

Hope this will help you..... ✌

Answer 2

Answer:

The age of her brother after 6 years is 15.

Step-by-step explanation:

Given:

5 years ago, a sister's age was 5 times the age of her brother, and the sum of present ages of sister and brother is 34 years.

To find:

The age of her brother after 6 years.

Step 1

Let the current age of the sister and her brother be x and y yrs old respectively.

Then, 5 years ago

Sister’s age existed 5 times the age of her brother

⇒ $x-5=5(y-5)$

$x=5y-25+5$

$x=5y-20$

Step 2

The totality of current ages is 34.

$x+y=34$

Solving equations,

$5y-20+y=34$

$6y=34+20=54$

$y=9$

Hence, her brother’s age after 6 years $= y + 6 = 9 + 6 = 15$ yrs.

Therefore, the age of her brother after 6 years is 15.

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