5 years ago, sisters age was 5 times the age of her brother and the sum of present ages of sister and brother is 34 years what will be the age of her brother after 6 year?
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Answered by
5
let present age of sister = x
let present age of brother = y
x + y = 34 [ given sum of present age = 34]
x = 34 - y ---------------------- eq 1
FIVE YEARS AGO
Age of Sister = x -5
Age of brother = y - 5
Given that (x - 5) = 5 × ( y - 5)
⇒ x - 5 = 5y - 25
⇒ x - 5y = - 20 -----------------------------eq 2
substituting value of x from eq1 in eq 2
(34 - y) - 5y = -20
⇒ 34 - 6y = -20
⇒ -6y = -54
⇒ y = 9
So Age of brother after 6 year = y + 6 = 9 + 6 = 15 years
Answered by
2
Let x and y be the present age of sister and brother.
x + y = 34.........(1)
x - 5 =5( y - 5)
x - 5 =5y - 25
x -5y= -20........(2)
Substracting eqn. (1) & (2), we get
-6y = -54
y = 9
Therefore, age of brother is 9.
After 6 years = y + 6
=9 + 6
= 15
x + y = 34.........(1)
x - 5 =5( y - 5)
x - 5 =5y - 25
x -5y= -20........(2)
Substracting eqn. (1) & (2), we get
-6y = -54
y = 9
Therefore, age of brother is 9.
After 6 years = y + 6
=9 + 6
= 15
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