Math, asked by rkr9708360787, 8 months ago

5 years ago the age of a was three times the age of b and after 10 years the age of a will be twice the age of b, then what is the present age of a and b.
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Answers

Answered by achauhansbs
0

Answer:

10 years from now A will be twice as old as B. 5 years ago A was 3 times as old as B. What are the present ages of A and B?

In these problems try not to calculate everything in your mind, but write them down in equations. They seem like riddles that your old great-uncle would say in a family dinner, but are simple if you think mathematically.

we assign a the age of A and b the age of B

10 years from now A will be twice as old as B

a + 10 = 2b

5 years ago A was 3 times as old as B

a - 5 = 3b

See? You just express the meaning of the words through equations. This is a simple set with 2 variables and 2 equations (the variables are the same number as the equations, so we can solve it). The simplest way to do so is write a as an expression of b, then replace that expression in the other equation. I will not proceed in solving it, as I believe that you have enough info and help to do it your self. Good luck!

Answered by 7dayushmam09
0

Answer is in the attachment

Please mark it as brainlliest answer.

Thank it too.

Hope it helps...

Thnku.

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