Question

 5 years ago, the age of father was 2.25 times the age of his son. 2 years hence, the age of father becomes 2.6 times the age of his daughter. If the son is 7 years elder to daughter, find the present age of Father. *​

Answer 1

Answer:

your Answer is that

according to your question

you age is your Answer

sorry for wrong Answer!!!

Answer 2

$i )present \;age \ : of \:the \: daughter = x$

$present \;age \ : of \:the \: son = (x+7) \: years$

$Present \:age \: of \:the \:father = y$

$ii) \underline { \pink { 5 \: years \:ago }}$

$Age \: of \:the \: daughter = (x-5) \: years$

$Age \: of \:the \: son = (x+7-5)\\= (x+2) \: years$

$Age \:of \: father = ( y - 5 ) \: years$

/* According to the problem given */

$y - 5 = 2.25( x+2)$

$\implies y = 2.25x + 4.5 + 5$

$\implies y = 2.25x + 9.5 \: --(1)$

$iii)\underline { \pink { after \:2\: years }}$

$Age \: of \:the \: daughter = (x+2) \: years$

$Age \: of \:the \: son = (x+7+2)\\= (x+9) \: years$

$Age \:of \: father = ( y +2 ) \: years$

/* According to the problem given */

$y + 2 = 2.6( x+2)$

$\implies y = 2.6x + 5.2 -2$

$\implies y = 2.6x + 3.2 \: --(2)$

/* From Equations (1) and (2), we get */

$2.6x + 3.2 = 2.25x + 9.5$

$\implies 2.6x - 2.25x = 9.5 - 3.2$

$\implies 0.35 x = 6.3$

$\implies x = \frac{6.3 }{0.35}$

$\implies x = 18$

/* Put x = 18 in equation (1), we get */

$y = 2.25\times 18 + 9.5\\= 40.5 + 9.5 \\= 50 \: years$

Therefore.,

$\red{Present \:age \: of \:the \:father}\green { = 50 \: years }$

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