Question

5 years ago the age of man os 7 times as old as his son . after 5 years the age of man is 3 times as old as his son . find their present ages​

Answer 1

Answer:

➡Let Five years ago the age of son be x years and age of father be 7x years.

➡Present age of son =x+5

➡Present age of father =7x+5

➡5 years later their age will (x+10) and (7x+10)

$➡∴7x+10=3(x+10) \\ ➡7x−3x=20 \\ ➡4x=20 \\ ➡x=5$

So, the present age of son=x+5=5+5=10years and the present age of father=7x+5=35+5=40years

Step-by-step explanation:

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