Math, asked by thamajanvijanvi4630, 1 year ago

5 years ago , the age of parvathi was 4 times the age of her son. The sum of their present ages is 55years. Find parvathi's present age

Answers

Answered by pavan6775
84
5 years ago
let age of son=x years
age of parvathi=4x years
present
age of son=x+5 years
age of parvathi=4x+5 years
sum of their ages=55 years
x+5+4x+5=55 years
5x+10=55 years
5x=45 years
x=9 years
age of son at present=9+5=14 years
age of parvathiat present=4×9+5=36+5=41 years
Answered by Anonymous
58

\bf{\Huge{\underline{\boxed{\sf{\pink{ANSWER\::}}}}}}

\bf{\Large{\underline{\bf{Given\::}}}}}

5 years ago, the age of Parvati was 4 times the age of her son. The sum of their present ages is 55 years.

\bf{\Large{\underline{\bf{To\:find\::}}}}}

The present age of Parvati's.

\bf{\Large{\underline{\bf{\blue{Explanation\::}}}}}

Let the present age of son be R years.

Let the present age of Parvati's be (55-R) years.

  • \bf{\large{\underline{\sf{\red{5\:years\:ago\::}}}}}

The age of son = (R-5) years.

The age of Parvati's = (55-5-R) years

A/q

→ 50 - R = 4(R - 5)

→ 50 - R = 4R - 20

→ -R - 4R = -20 - 50

→ -5R = -70

→ R = \bf{\cancel{\frac{-70}{-5} }}

→ R = 14 years.

Thus,

The present age of Parvati's = (55 - 14) years

The present age of Parvati's = 41 years.

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