5 years ago the average age of a,b,c,and d was 45.with e joining the average age of all the five is 49 years .how old e?
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Let the ages of a,b,c and d 5 years ago be a-5, b-5, c-5 and d-5
their averages is (a+b+c+d - 20)/ 4 = 45
a+b+c+d = 200
age of e 5 years ago is e - 5
(a+b+c+d+e-25)/5 = 49
a+b+c+d+e = 270
200 + e = 270
e = 70
their averages is (a+b+c+d - 20)/ 4 = 45
a+b+c+d = 200
age of e 5 years ago is e - 5
(a+b+c+d+e-25)/5 = 49
a+b+c+d+e = 270
200 + e = 270
e = 70
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