5 years ago the average age of a family which includes father, mother and a son was 35 years. 3 years ago the average age of father and mother was 46 years. What is the present age (in years) of the son?
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Answer:
22years
Step-by-step explanation:
Let the agesof members in a family ,
PRESENT AGES:
father be 'a'
mother be 'b'
son be 'c'
AGES before 5years
father be 'a-5'
mother be 'b-5'
son be 'c-5'
5 years ago the average age of a family which includes father, mother and a son was 35 years
so,(a-5+b-5+c-5)/3=35
a+b+c=3(35)+15
a+b+c=120. _3
AGES before 3years
father be 'a-3'
mother be 'b-3'
son be 'c-3'
3 years ago the average age of father and mother was 46 years.so,
(a-3+b-3)/2=46
a+b-6=92
a+b=98. _2
from equations 1&2.we get,
c=120-98
c=22
The present age (in years) of the son is 22years
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