Question

5 years before, father was 4 times the age of his son. After 15 years, father's age will be twice the age of his son. Find their present ages.​

Answer 1

Step-by-step explanation:mark it brainliest

let age of son 5 years before be x years

father age 5years before=4x

present age of son and father=x+5 and 4x+5

Their age after 15 years=x+5+15 and 4x+5+15

according to question,

4x+20=2(x+20)

4x+20=2x+40

2x=20

x=10

hence,present age of son=10+5=15

fathers present age=45years