Math, asked by deleepdgreat, 5 months ago

.5 years, hence the age of Jacob will be three times that of his son, 5 years ago, Jacob’s age was seven times that of his son, what are their present ages?​

Answers

Answered by nikunjc971
1

Step-by-step explanation:

Let 'x' be the present age of jacob and 'y' be the age of his son

As per question

x+5=3(y+5).....(1)

x−5=7(y−5).......(2)

Adding (1) and (2)

2x=3y+15+7y−35

2x=10y−20

x=5y−10...(3)

Putting (3) in (1)

5y−5=3y+15

2y=20

y=10

Putting in (3)

x=5×10−10

x=40

Therefore Present age of Jacob is 40 years and his son is 10 years

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