5 yrs ago a man was 7 times as old as his son. 5 yrs hence the father will 3 times as old as his son . what is present age of son
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Answer:
10 years old
Step-by-step explanation:
let, present age of son be x and present age of Father be y.
5 years ago, (y-5) = 7(x-5)
5 years later, (y+5) = 3(x+5)
subtract eq. 2 from eq. 1
y - 5 - y - 5 = 7x - 35 - 3x -15
-10 = 4x - 50
4x = 40
x = 10
present age of son is 10 years.
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