Question

5 yrs ago a man was 7 times as old as his son. After 5 yrs, the father will be 3 times as old as his son. Find their present ages.

Answer 1

Answer:

here is the answer

Step-by-step explanation:

Age of the son =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age =10

father age =7x+5=7*5+5=40

Answer 2

Answer:

The son is 10 years old. And his father is 40 years old.

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years