Question

5 yrs ago the average age of a,b,c and d was 45 yrs.wtithjoining of e the average age of all the five years is 49 yrs.how old is e

Answer 1

Sum of a,b,c,d ( 5 yrs ago ) = 45 x 4 = 180 yrs

Sum of present age = 180 + ( 5 x 4 ) = 200 yrs

Now, sum of age of a,b,c,d,e = 49 x 5 = 245 yrs

Age of e = 245 - 200 = 45 yrs

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