5 (Z+3)=4(2z+2) solve it
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Distribute
Distribute5(+3)=4
Distribute5(+3)=4(2+2)
5(z+3)=4(2z+2){\color{#c92786}{5(z+3)}}=4(2z+2)5(z+3)=4(2z+2)
5+15=4 (2+2)
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