50.0 cm of 1.0 mol dm hydrochloric acid reacts with 50.0 cm of 10 moldim sodium
hydroxide. The temperature rises to 6.5°C. Calculate the enthalpy of neutralization. Specific heat
capacity of water is 4.18 Jg'°C!
A) -54.0 Kimo!!
C) +54.0 Kmol
B) +58.8 KJmol
D) -58.8Kimo!
Answers
Answered by
2
Answer:
d is best answer for this question
MARK ME AS BRAINLLEST
Similar questions