50.0mL of butane Gas at STP contains how many molecules?
Answers
Answered by
0
Answer:
at STP ( 0∘C and 1atm), 1 mole of an ideal gas occupies
22.4 dm3
This means 1 mole of butane has a volume of 22.4dm3 at STP.
∴
V = 22.4 dm3
=22.4×10^3cm^3
1 mole of butane has the same mass in grams as its relative molecular mass.
M
r
=
4
×
12
+
10
×
1
=
58
∴
m
=
58
g
=
58
×
10
−
3
k
g
Using
ρ
=
m
v
where
ρ
is density:
ρ
=
58
22.4
×
10
3
=
2.59
×
10
−
3
g cm
−
3
or
2.59
kg m
−
3
Similar questions