Question

ᴀ ᴄᴏɴꜱᴛᴀɴᴛ ʀᴇᴛᴀʀᴅɪɴɢ ꜰᴏʀᴄᴇ ᴏꜰ 50 ɴ ɪꜱ ᴀᴘᴘʟɪᴇᴅ ᴛᴏ ᴀ ʙᴏᴅʏ ᴏꜰ ᴍᴀꜱꜱ 20 ᴋɢ ᴍᴏᴠɪɴɢ ɪɴɪᴛɪᴀʟʟʏ ᴡɪᴛʜ ᴀ ꜱᴘᴇᴇᴅ ᴏꜰ 15 ᴍ/ꜱ. ᴛʜᴇ ᴛɪᴍᴇ ᴛᴀᴋᴇɴ ʙʏ ᴛʜᴇ ʙᴏᴅʏ ᴛᴏ ꜱᴛᴏᴘ ɪꜱ: *​

Answer 1

Answer:

Given that

Force F= 50N

Mass m = 20kg

Initial velocity u =15 m per sec

Now from newtons second law

F= ma

50= 20×a

a= 2.5 m per sec square

Now from equation of motion

v= u+at

0= 15+(-2.5 ) t

t= 15/2.5

t= 6 sec

hence the body will stop at 6 sec

Answer 2

$\bf\large\underline\blue{Given:—} \\ \cal☛︎ Force, F = 50 N \\ \cal ☛︎ Mass, m = 20 kg \\ \cal☛︎ Initial \: velocity, u = 15 m/s \\ \\ \\ \bf\large\underline\blue{To\:find:—} \\ \cal \: How long \: does \: the \: body \: take \: to \: stop ? \\ \\ \\ \bf\large\underline\blue{Solution:—} \\ \tt \: From \: Newton's \: second \: law,we \: know \: that \\ \boxed{\bf{\red{★ F=ma}}} \\ ↦50 = 20 × a m/s \\ ↦a = 2.5 m/s \\ \\ \tt Now, \: as \: per \: first \: equation \: of \: motion:- \\ \boxed{\bf{\green{★ v=u+at}}} \\ ↦0 = 15 + (-2.5)×t \\ ↦t = 15/2.5 \\ \\ \boxed{\bf{\purple{t=6\:s}}} \\ \bf \: \small{Hence, the time taken by the body to stop is 6 seconds.}$