Question

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50
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10. The lengths of two parallel sides of a trapezium are 28 cm and 40 cm. If the lengths of each of its other
two sides be 12 cm, then find the area of the trapezium?
11. Find the unknown angles in the following figures.
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Answer 1

Answer of question no.10

As the other 2 sides are equal 12cm each

it is an iso celestrapezium,

To find height h of the trapezium:

In the Rt.angle triangle

base of the triangle = (40-28)/2 = 12/2=6cm

hypotenuse=12 base=6

height=v 12^2-6^2 = 10.4 cm

Area of trapezium=1/2h (a+b)

a,b are parallel sides 40 and 28

Area = 1/2 x 10.4 (40+28)

5.2x68=353.6 cm2

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