Question

50. A block of wood of mass 9.8 kg is suspended
by a string. A bullet of mass 200 gm strikes
horizontally with a velocity of 100 ms and
gets embedded in it. The maximum height
attained by the block is (g = 10 ms?)
1) 0.1 m 2) 0.2 m 3) 0.3 m 4)Om​

Answer 1

Answer:

Answer:0.2m

Explanation:mu+Mu'=(M+m)v

m=mass of block

M=mass of bullet

u=initial velocity of block

u'=initial velocity of bullet

v=final velocity of system

9.8(0)+0.2(100)=(9.8+0.2)v

v=2

h=v^2/2g

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