Question

50. A bullet of 30gm is horizontally fired with a velocity 180 ms from a gun of mass
3 kg. The velocity of recoil of the gun is :
3 kg.
(a) 2.5 ms-¹ (b) 1.8 ms–¹ (c ) 4.8 ms–¹ (d) 5.5 ms- |
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Answer 1

Answer:

Answer = 1.8 m/s

Explanation:

Let recoil velocity be v.

Velocity of bullet = 180 m/s

Mass of bullet = 30 gm = 0.03 kg

Mass of gun = 3kg

Momentum of gun = bullet

=> 0.03 × 180 = 3 × v

=> 5.4 = 3v

=> v = 1.8 m/s

Answer = 1.8 m/s

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Answer 2

Here is your answer. Please mark as brainliest as it helps a lot. Thank you!