Question

50.
A fuel cell involves combustion of methane at 1 atm and 298 K
CH4(g) +202
→CO
2(g)
+2H,00); AH° =-890 kJ. Calculate the efficiency (Ecell =1.09 V)
2) 0.85
3) 0.74
4) 0.58
1) 0.94
7​

Answer 1

Answer:

hh

Explanation:

hbvvjvbkk igloo FL cl vl l

Answer 2

Answer:0.94

Explanation:G°= -nfE°cell

=-8✖96500✖1.09

=-841.48KJ/mol

Efficiency=G°/H

=-841.48/-890

=0.94

(n=8 change in oxidation state of carbon.4-(-4)=8)