50. A rocket is launched with an initial velocity of 100 meters per second. Its height above the ground after t seconds is given by the formula h(t) = 1001 - 5t2, where h(t) represents the height in meters. What is the height of the rocket 10 seconds after it is launched?
Answers
Step-by-step explanation:
h(t) = -5t² + 100t
h(t) represents height in metres and t for time.
- To find :- height of the rocket 10 seconds
So, t = 10
Putting the value of t in equation....
h(t) = -5(100) + 100(10)
h(t) = -500 + 1000
h(t) = 500 m
Given : A model rocket is launched from the ground. The height h reached by the rocket after t seconds
h(t)= 100t - 5t² ( correct in Question 1001 is 100t)
To Find : . What is the height of the rocket 10 seconds after it is launched
Solution:
h(t)=-100t - 5t²
Substitute t = 10
=> h(10) = 100(10) - 5(10)²
=> h(10) = 1000 - 500
=> h(10) = 500
Hence the height of the rocket 10 seconds after it is launched is 500 m .
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