Question

50 cc of 0.1 M copper sulphate is diluted to 100 cc by adding water. What is the new molarity of the solution

Answer 1

Answer:

M1.V1=M2.V2

50 x 0.1 = M2 x 100

M2= 5/100 = 0.05 M

or simply volume has been increased to double and hence concentration reduces to half i.e. 0.05 M.

Ans: 0.05 M

Hope this answer serves your purpose. Thanks..

Answer 2

Answer:

Explanation:

Since the number of moles are constant therefore

M1V1 = M2V2

0.1 X 50 = M2 X 100

M2=(0.1x50)/100

M2 = 5/100

M2 = 0.05M

Final ans :- 0.05M

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