Question

50 cc of oxygen is collected in an inverted gas jar over water. The atmospheric pressure is 99.4 kPa and the room temperature is 27°C. The water level in the jar is same as the level outside. The saturation vapour pressure at 27°C is 3.4 kPa. Calculate the number of moles of oxygen collected in the jar.

Answer 1

Answer:

:

Pressure inside the tube

= Atmospheric pressure

= 99.4 K Pa

pressure exerted by O2 vapour

= Atmospheric pressure V.P.

= 99.4 K Pa - 3.4 K Pa

=96 K Pa

Ifνmberofmo≤of O_2=n

Then using gas equation

96×(103)×50×(10−6)

=n×8.3×300

rArr n= ( 96 xx 50 xx (10^3)/8.3 xx 300) =1.9277 xx(10^-3)

FOLLOW ME

Explanation:

Answer 2

Answer:

:

Pressure inside the tube

= Atmospheric pressure

= 99.4 K Pa

pressure exerted by O2 vapour

= Atmospheric pressure V.P.

= 99.4 K Pa - 3.4 K Pa

=96 K Pa

Ifνmberofmo≤of O_2=n

Then using gas equation

96×(103)×50×(10−6)

=n×8.3×300

rArr n= ( 96 xx 50 xx (10^3)/8.3 xx 300) =1.9277 xx(10^-3)

FOLLOW ME

Explanation: