50 cc of oxygen is collected in an inverted gas jar over water. The atmospheric pressure is 99.4 kPa and the room temperature is 27°C. The water level in the jar is same as the level outside. The saturation vapour pressure at 27°C is 3.4 kPa. Calculate the number of moles of oxygen collected in the jar.
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Answered by
35
Answer:
Pressure inside the tube
= Atmospheric pressure
= 99.4 K Pa
pressure exerted by O2 vapour
= Atmospheric pressure V.P.
= 99.4 K Pa - 3.4 K Pa
=96 K Pa
Ifνmberofmo≤of O_2=n
Then using gas equation
96×(103)×50×(10−6)
=n×8.3×300
rArr n= ( 96 xx 50 xx (10^3)/8.3 xx 300) =1.9277 xx(10^-3)
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Answered by
9
Answer:
Pressure inside the tube
= Atmospheric pressure
= 99.4 K Pa
pressure exerted by O2 vapour
= Atmospheric pressure V.P.
= 99.4 K Pa - 3.4 K Pa
=96 K Pa
Ifνmberofmo≤of O_2=n
Then using gas equation
96×(103)×50×(10−6)
=n×8.3×300
rArr n= ( 96 xx 50 xx (10^3)/8.3 xx 300) =1.9277 xx(10^-3).`
FOLLOW ME
Step-by-step explanation:
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