50 circular plates each of dameter 14 cm and thickness 0.5 cm are placed one above the other to form a right circular cylinder . find its total surface area.
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Radius of the cylinder=radius of the plate=r=7cm
Height of the cylinder=h= No. of plates × thickness of one plate=50×1/2 =25 cm
∴, total surface area= curved surface area+ 2×area of tha base
=2πrh+2πr²
=2πr(h+r)
=2×22/7×7(25+7)
=44×32
=1408 cm²
Volume of the cylinder
=πr²h
=22/7×7²×25
=22×7×25
=3850 cm³
∴, total surface area is 1408 cm² and volume is 3850 cm³. Ans.
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Answer No. Of circular plates =50
Thickness of each plate =0.5 cm
diameter of each circular plate =14 cm
Now,
Total height of new right circular cylinder plates so firmed =50×0.5 cm= 25 cm
Diameter =14 cm
Radius =7 cm
T.S.A =2 pie r ×(h+r)
={2×22/7×7×(25+7)} cm
=(44×32) cm=1408 cm
Step-by-step explanation:
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