50 CIRCULAR PLATES EACH OF DIAMETER 14 CM AND THICKNESS 0.5 CM ARE PLACED ONE ABOVE THE OTHER TO FORM A RIGHT CIRCULAR CYLINDER . FIND THE TOTAL SURFACE AREA OF A CYLINDER.
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1
2×22/7×14(14+5/10)
=616 surface area of 1 plate
surface area of 50 plates
=616×50
=30800 cm^2
=616 surface area of 1 plate
surface area of 50 plates
=616×50
=30800 cm^2
darshpreet:
thats the wrong way
sorry i forget to half the daimeter
Answered by
3
the answer is 3256/7
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