50 circular plates each of diameter 14 cm and thickness 0.5 cm are placed one above the other two form a right circular cylindrical. Find its total surface area
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Answered by
0
Answer:
50 circular plate
diameter of plate =14cm
Radius of plate = d/2=
2
14
=7cm
thickness =0.5cm
→ Height of the cylinder = No. of plates × thickness of plate
=50×0.5
=25cm
→ total surface Area = curved surface + 2 × area of base
=2πr.h+2×πr
2
=2πr(h+r)
=2π×7(25+7)
=2×
7
22
×7×32
=1408cm square
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Answered by
0
Answer:
Step-by-step explanation:
total height= 50*0.5
= 25 cm
the area of the circle ==
22/7*r^2
r=7
22*7*7/7
=22*7
=154
2 side so 154*2
308cm^2
the standing side is a folded rectangle so area +bh
b=
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