50 circular plates each of diameter 14 cm and thickness 0.5 cm are placed one above the other to form a right circular cylinder. Find its total surface area.
Answers
Answer:
The total surface area of the cylinder is 1408 cm² .
Step-by-step explanation:
Given :
Number of circular plates = 50
Diameter of each circular plate = 14 cm
Radius of each circular plate = 14/2 = 7 cm
Thickness of circular plates = 0.5 cm
Total thickness of plates, h = 0.5 × 50 = 25 cm
Plates are placed one above other so they form a cylinder.
Total surface area of a cylinder = 2πr(h + r)
= 2 × 22/7 ×7(25 + 7)
= 44 × 32
Total surface area of a cylinder = 1408 cm²
Hence, the total surface area of the cylinder is 1408 cm² .
HOPE THIS ANSWER WILL HELP YOU...
Here Given that the 50 circular plates each with diameter 14 cm.
Radius of circular plates =7 cm
Thickness of plates =0.5 cm
Since these plates are one above the other so total thickness of plates =0.5 *100
=25cm
Total surface area of a cylinder
= 2∏r×h+2∏r2
2∏r(h+r)
2×227×7(25+7)
Total surface area =1408 cm2
The total surface area of the cylinder is 1408 cm2.
Hope its help you