Question

50 ⓟⓞⓘⓝⓣⓢ

ⓟⓛⓩ ⓓⓞⓝⓣ ⓢⓟⓐⓜ ❤

class-12____sub-chemistry
_______chapter-Solutions​

Answer 1

Raoult's law explains partial vapour pressure of volatile component of the solution. ... According to Henry's law,pressure is directly proportional to the mole fraction of gas. P = KH X. When KH and P⁰ are same ,thenRaoult's law becomes special case ofHenry's law.

Answer 2

Henry's Law :

The law states that at a constant temperature, solubility of gas in a liquid is directly proportional to the partial pressure of gas present above the surface of the liquid / solution.

$\boxed{\mathsf{p\:{\propto{\chi}}}}$

$\boxed{\mathsf{p\:=\:K_{H} {\chi}}}$

↪️ p = Partial pressure of the gas.

↪️ $\mathsf{K_H}$ = Henry's Law constant

↪️ $\mathsf{\chi}$ = Mole Fraction of gas.

$\mathsf{p\:=\:K_{H} {\dfrac{n_g}{n_g\:+\:n_l}}}$

$\mathsf{\dfrac{p} {K_H} \:=\:{\dfrac{n_g}{n_g\:+\:n_l}}}$

➡️ $\boxed{\mathsf{\dfrac{p} {K_H} \:=\:{\dfrac{n_g}{n_l}}}}$

↪️ $\mathsf{n_g}$ in case of denominator will be neglected.

Raoult's Law :

It states that for a solution of volatile liquids, the partial pressure of each component is directly proportional to its mole fraction.

$\boxed{\mathsf{p\:{\propto{\chi}}}}$

$\boxed{\mathsf{p\:=\:{p}^{\circ}{\chi}}}$

In case of Binary Solution :

$\mathsf{p_A\:{\propto{\chi}_A}}$

$\mathsf{p_A\:=\:{p_A}^{\circ}{\chi}_A}$

$\mathsf{p_B\:{\propto{\chi}_B}}$

$\mathsf{p_B\:=\:{p_B}^{\circ}{\chi}_B}$

Where

↪️ $\mathsf{p_A}$ & $\mathsf{p_B}$ are Partial Vapour Pressure.

↪️$\mathsf{{\chi}_A}$ & $\mathsf{{\chi}_B}$ are Mole Fractions.

↪️ $\mathsf{{p_A} ^{\circ}}$ & $\mathsf{{p_B}^{\circ}}$ are Vapour Pressure of Pure component of A & B.