50 cm3 ethylene glycol (CH2OH-CH2OH)is dissolved in 50 gm water .The freezing point of mixture is -34 degree celcius .if freezing point of pure water is 0 degree celcius.Find density of ethylene glycol.
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Explanation:
Calculation of Molality :
Mass of ethylene glycol = 222.6 (Given)
Molar mass of ethylene glycol [C2H4(OH)2]
= 2 X 12 + 6 x 1 + 2 x 16
= 62
Therefore moles of ethylene glycol
= 222.6g / 62 gmol-1
= 3.59 mol
Mass of water = 200g (Given)
Therefore molality of the solution is = (moles of ethylene glycol / mass of water) x 1000
= (3.59 / 200) x 1000
= 17.95 m
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