50 cm³ of 0.2 n hcl is titrated against 0.1 n naoh solution. The titration was discontinued after adding 50 cm³ of naoh. The remaining titration is completed by adding 0.5 n koh. The volume of koh required for completing the titration is (karnataka, 2011)
Answers
Answered by
3
Answer:
Explanation:
n1v1=n2v2
0.1*50=0.5*v2
0.1/0.5*50
50/5
10cm^3
Answered by
3
The volume of KOH required for completing the titration is
Explanation:
To calculate the volume of KOH, we use the equation given by neutralization reaction:
where,
are the normality and volume of acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
are the n-factor, molarity and volume of base which is KOH
We are given:
Putting values in above equation, we get:
Learn more about neutralization reaction:
https://brainly.in/question/11899192
https://brainly.in/question/11716499
#learnwithbrainly
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