50 coulomb charge charge is brought from infinity to a given point in an electric field when 62.5 joule of work is done what is potential at that point
Answers
Answered by
28
Potential = work÷charge
= 62.5÷50
1.25 Volt
= 62.5÷50
1.25 Volt
Answered by
9
Answer:
Explanation:
work÷charge = 62.5÷50 = 1.25 Volt
Similar questions