50 daily workers can complete a dam project in 40 days. If 30 of them work daily and the rest work in every alternative day, how many more days will be required to complete the project.
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Total work= 50*40= 2000
In 40 days, daily workers complete: 30*40=1200
Alternate workers complete:20 * (40/2) = 400
Let us assume that they work for x days after 40 days.
Alternate workers will work for x/2 days.
A/Q, 2000 = 1200 + 400 + 30x + 20*(x/2)
Solving, we get x=10
Ans: 10 days
Another Approach:
Total Works: 50*40=2000
30*40=1200
20*20=400
Total =1600
1600….4/5…… 40 days
Total Works: 50*40=2000
30*40=1200
20*20=400
Total =1600
2000………. 1 work
1600…………1600/2000 work or 4/5 work
remain, 1- 4/5=1/5 work
1600….4/5…… 40 days
1600…..1……….(40*5)/4=50
1600…..1/5……..50/5 =10 days
In 40 days, daily workers complete: 30*40=1200
Alternate workers complete:20 * (40/2) = 400
Let us assume that they work for x days after 40 days.
Alternate workers will work for x/2 days.
A/Q, 2000 = 1200 + 400 + 30x + 20*(x/2)
Solving, we get x=10
Ans: 10 days
Another Approach:
Total Works: 50*40=2000
30*40=1200
20*20=400
Total =1600
1600….4/5…… 40 days
Total Works: 50*40=2000
30*40=1200
20*20=400
Total =1600
2000………. 1 work
1600…………1600/2000 work or 4/5 work
remain, 1- 4/5=1/5 work
1600….4/5…… 40 days
1600…..1……….(40*5)/4=50
1600…..1/5……..50/5 =10 days
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