Question

50
EXERCISE 11.1
1. In A ABC, right-angled at B, AB= 24 cm, BC = 7 cm. Determine:
(i) sin A, cos A
(ú) sin C, cos C
​

Answer 1

Hey friend, Here is your answer-

Triangle ABC is right angled triangle,

By using Pythagores theorem,

AB^2 + BC^2 = AC^2

24^2 + 7^2 = AC^2

576 + 49 = AC^2

625 = AC^2

AC = 25 cm

i) Sin A = BC / AC

= 7 / 25

Cos A = AB / AC

= 24 / 25

ii)Sin C = AB / AC

= 24 / 25

Cos C = BC / AC

= 7 / 25

Hope it will help you.

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