Chemistry, asked by zuhrawani321, 11 months ago

50 grams of 80%caco3 is heated to calculate the volume of co2 produced at Ntp

Answers

Answered by anwesha2672

4

50g of 80% CaCO3 implies that pure calcium carbonate is just

80/100*50g=40g

40g calcium carbonate implies 0.4mol

According to reaction

No. Of moles of carbon dioxide = 0.4mol

Volume at NTP

=> 0.4*22.4L

Which is equal to 8.96L

Hope it helps

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