Question

50 grams of water at 20 degree celsius is mixed with 50 grams of water at t degree Celsius if the final temperature is 30 degree Celsius t degrees ce
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Answer 1

Answer:

30°C

Explanation :

Given,

Mass m1 = 50g

Let's assume

Temperature T1 = 40°C

Mass m2 = 50g

Temperature T2 = 20°C

By using method of mixtures,

Final temperature

T = m1T1 + m2T2/m1 +m2

= 50×40+50×20/50+50

= 2000+1000/100

= 30°C

The final temperature = 30°C

So the required temperature is 40°C