Question

50. If 8% of x and 12% of y are equal, then by how much percent is x greater than y
than y?
th e answer is 33.33percent but how pls solve my question ​

Answer 1

x is greater than y by 33.33%.

Step-by-step explanation:

We are given that 8% of x is 12% of y are equal.

So, $\frac{8}{100}x = \frac{12}{100}y$

⇒ 0.08x = 0.12y

⇒ $y = \frac{0.08}{0.12}x = \frac{2}{3}x$ .............. (1)

Now, we have to find the percentage by which x is greater than y.

So, the % is = $\frac{x - y}{x} \times 100 \% = \frac{x - \frac{2}{3}x }{x} \times 100\% = \frac{1}{3} \times 100\% = 33.33\%$.

Therefore, x is greater than y by 33.33%. (Answer)

Answer 2

Answer:

x  is greater than y by 33.33%

Step-by-step explanation:

0.08x  = 0.12y

therefore 8x  = 12y

therefore 2x  = 3y

therefore y = (2/3) x  = 0.667 x

therefore x  - y = x  - 0.667x  = 0.333x

therefore x  is greater than y by 33.33%